Made Easy Chemistry: ELECTRONIC STRUCTURES

ELECTRONIC STRUCTURES This page explores how you write electronic structures for atoms using s, p, and d notation. It assumes that you know about simple atomic orbitals - at least as far as the way they are named, and their relative energies. If you want to look at the electronic structures of simple monatomic ions (such as Cl^-, Ca²⁺ and Cr³⁺), you will find a link at the bottom of the page.

The electronic structures of atoms Relating orbital filling to the Periodic Table

UK syllabuses for 16 - 18 year olds tend to stop at krypton when it comes to writing electronic structures, but it is possible that you could be asked for structures for elements up as far as barium. After barium you have to worry about f orbitals as well as s, p and d orbitals - and that's a problem for chemistry at a higher level. It is important that you look through past exam papers as well as your syllabus so that you can judge how hard the questions are likely to get.
This page looks in detail at the elements in the shortened version of the Periodic Table above, and then shows how you could work out the structures of some bigger atoms.

The first period
Hydrogen has its only electron in the 1s orbital - 1s¹, and at helium the first level is completely full - 1s².
The second period
Now we need to start filling the second level, and hence start the second period. Lithium's electron goes into the 2s orbital because that has a lower energy than the 2p orbitals. Lithium has an electronic structure of 1s²2s¹. Beryllium adds a second electron to this same level - 1s²2s².
Now the 2p levels start to fill. These levels all have the same energy, and so the electrons go in singly at first.

B		1s²2s²2p_x¹
C		1s²2s²2p_x¹2p_y¹
N		1s²2s²2p_x¹2p_y¹2p_z¹

The next electrons to go in will have to pair up with those already there.

O		1s²2s²2p_x²2p_y¹2p_z¹
F		1s²2s²2p_x²2p_y²2p_z¹
Ne		1s²2s²2p_x²2p_y²2p_z²

You can see that it is going to get progressively tedious to write the full electronic structures of atoms as the number of electrons increases. There are two ways around this, and you must be familiar with both.
Shortcut 1: All the various p electrons can be lumped together. For example, fluorine could be written as 1s²2s²2p⁵, and neon as 1s²2s²2p⁶.
This is what is normally done if the electrons are in an inner layer. If the electrons are in the bonding level (those on the outside of the atom), they are sometimes written in shorthand, sometimes in full. Don't worry about this. Be prepared to meet either version, but if you are asked for the electronic structure of something in an exam, write it out in full showing all the p_x, p_y and p_z orbitals in the outer level separately.
For example, although we haven't yet met the electronic structure of chlorine, you could write it as 1s²2s²2p⁶3s²3p_x²3p_y²3p_z¹.
Notice that the 2p electrons are all lumped together whereas the 3p ones are shown in full. The logic is that the 3p electrons will be involved in bonding because they are on the outside of the atom, whereas the 2p electrons are buried deep in the atom and aren't really of any interest.
Shortcut 2: You can lump all the inner electrons together using, for example, the symbol [Ne]. In this context, [Ne] means the electronic structure of neon - in other words: 1s²2s²2p_x²2p_y²2p_z² You wouldn't do this with helium because it takes longer to write [He] than it does 1s².
On this basis the structure of chlorine would be written [Ne]3s²3p_x²3p_y²3p_z¹.
The third period
At neon, all the second level orbitals are full, and so after this we have to start the third period with sodium. The pattern of filling is now exactly the same as in the previous period, except that everything is now happening at the 3-level.
For example:

		short version
Mg	1s²2s²2p⁶3s²	[Ne]3s²
S	1s²2s²2p⁶3s²3p_x²3p_y¹3p_z¹	[Ne]3s²3p_x²3p_y¹3p_z¹
Ar	1s²2s²2p⁶3s²3p_x²3p_y²3p_z²	[Ne]3s²3p_x²3p_y²3p_z²

The beginning of the fourth period
At this point the 3-level orbitals aren't all full - the 3d levels haven't been used yet. But if you refer back to the energies of the orbitals, you will see that the next lowest energy orbital is the 4s - so that fills next.

K		1s²2s²2p⁶3s²3p⁶4s¹
Ca		1s²2s²2p⁶3s²3p⁶4s²

There is strong evidence for this in the similarities in the chemistry of elements like sodium (1s²2s²2p⁶3s¹) and potassium (1s²2s²2p⁶3s²3p⁶4s¹)
The outer electron governs their properties and that electron is in the same sort of orbital in both of the elements. That wouldn't be true if the outer electron in potassium was 3d¹.
s- and p-block elements

The elements in Group 1 of the Periodic Table all have an outer electronic structure of ns¹ (where n is a number between 2 and 7). All Group 2 elements have an outer electronic structure of ns². Elements in Groups 1 and 2 are described as s-block elements.
Elements from Group 3 (the boron group) across to the noble gases all have their outer electrons in p orbitals. These are then described as p-block elements.

d-block elements
We are working out the electronic structures of the atoms using the Aufbau ("building up") Principle. So far we have got to calcium with a structure of 1s²2s²2p⁶3s²3p⁶4s².
The 4s level is now full, and the structures of the next atoms show electrons gradually filling up the 3d level. These are known as d-block elements.

Once the 3d orbitals have filled up, the next electrons go into the 4p orbitals as you would expect.
d-block elements are elements in which the last electron to be added to the atom using the Aufbau Principle is in a d orbital.
The first series of these contains the elements from scandium to zinc, which at GCSE you probably called transition elements or transition metals. The terms "transition element" and "d-block element" don't quite have the same meaning, but it doesn't matter in the present context.

d electrons are almost always described as, for example, d⁵ or d⁸ - and not written as separate orbitals. Remember that there are five d orbitals, and that the electrons will inhabit them singly as far as possible. Up to 5 electrons will occupy orbitals on their own. After that they will have to pair up.
d⁵ means

d⁸ means

Notice in what follows that all the 3-level orbitals are written together - with the 4s electrons written at the end of the electronic structure.

Sc		1s²2s²2p⁶3s²3p⁶3d¹4s²
Ti		1s²2s²2p⁶3s²3p⁶3d²4s²
V		1s²2s²2p⁶3s²3p⁶3d³4s²
Cr		1s²2s²2p⁶3s²3p⁶3d⁵4s¹

Whoops! Chromium breaks the sequence. In chromium, the electrons in the 3d and 4s orbitals rearrange so that there is one electron in each orbital. It would be convenient if the sequence was tidy - but it's not!

Mn	1s²2s²2p⁶3s²3p⁶3d⁵4s²	(back to being tidy again)
Fe	1s²2s²2p⁶3s²3p⁶3d⁶4s²
Co	1s²2s²2p⁶3s²3p⁶3d⁷4s²
Ni	1s²2s²2p⁶3s²3p⁶3d⁸4s²
Cu	1s²2s²2p⁶3s²3p⁶3d¹⁰4s¹	(another awkward one!)
Zn	1s²2s²2p⁶3s²3p⁶3d¹⁰4s²

And at zinc the process of filling the d orbitals is complete.
Filling the rest of period 4
The next orbitals to be used are the 4p, and these fill in exactly the same way as the 2p or 3p. We are back now with the p-block elements from gallium to krypton. Bromine, for example, is 1s²2s²2p⁶3s²3p⁶3d¹⁰4s²4p_x²4p_y²4p_z¹.

Summary
Writing the electronic structure of an element from hydrogen to krypton

Use the Periodic Table to find the atomic number, and hence number of electrons.

Fill up orbitals in the order 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p - until you run out of electrons. The 3d is the awkward one - remember that specially. Fill p and d orbitals singly as far as possible before pairing electrons up.

Remember that chromium and copper have electronic structures which break the pattern in the first row of the d-block.

Writing the electronic structure of big s- or p-block elements

First work out the number of outer electrons. This is quite likely all you will be asked to do anyway.
The number of outer electrons is the same as the group number. (The noble gases are a bit of a problem here, because they are normally called group 0 rather then group 8. Helium has 2 outer electrons; the rest have 8.) All elements in group 3, for example, have 3 electrons in their outer level. Fit these electrons into s and p orbitals as necessary. Which level orbitals? Count the periods in the Periodic Table (not forgetting the one with H and He in it).
Iodine is in group 7 and so has 7 outer electrons. It is in the fifth period and so its electrons will be in 5s and 5p orbitals. Iodine has the outer structure 5s²5p_x²5p_y²5p_z¹.
What about the inner electrons if you need to work them out as well? The 1, 2 and 3 levels will all be full, and so will the 4s, 4p and 4d. The 4f levels don't fill until after anything you will be asked about at A'level. Just forget about them! That gives the full structure: 1s²2s²2p⁶3s²3p⁶3d¹⁰4s²4p⁶4d¹⁰5s²5p_x²5p_y²5p_z¹.
When you've finished, count all the electrons to make sure that they come to the same as the atomic number. Don't forget to make this check - it's easy to miss an orbital out when it gets this complicated.
Barium is in group 2 and so has 2 outer electrons. It is in the sixth period. Barium has the outer structure 6s².
Including all the inner levels: 1s²2s²2p⁶3s²3p⁶3d¹⁰4s²4p⁶4d¹⁰5s²5p⁶6s².
It would be easy to include 5d¹⁰ as well by mistake, but the d level always fills after the next s level - so 5d fills after 6s just as 3d fills after 4s. As long as you counted the number of electrons you could easily spot this mistake because you would have 10 too many.